4x^2+42x+54=0

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Solution for 4x^2+42x+54=0 equation:



4x^2+42x+54=0
a = 4; b = 42; c = +54;
Δ = b2-4ac
Δ = 422-4·4·54
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-30}{2*4}=\frac{-72}{8} =-9 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+30}{2*4}=\frac{-12}{8} =-1+1/2 $

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